x^2+134x-1136=0

Solution for x^2+134x-1136=0 equation:

x^2+134x-1136=0

a = 1; b = 134; c = -1136;
Δ = b2-4ac
Δ = 1342-4·1·(-1136)
Δ = 22500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{22500}=150$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(134)-150}{2*1}=\frac{-284}{2}
=-142
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(134)+150}{2*1}=\frac{16}{2}
=8
$